A grinding wheel having a diameter of 200 mm rotates at 3 000 r/min with a tangential force of 40 N on the workpiece. The motor runs at 1 500 r/min and the efficiency of the machine is 72%.

Calculate the input power of the motor

1 answer

To calculate the input power of the motor, we first need to determine the useful power being delivered to the grinding wheel and then account for the efficiency of the machine.

Step 1: Calculate the Tangential Speed of the Grinding Wheel

The tangential speed \( V \) of the grinding wheel can be calculated using the formula:

\[ V = \pi \times D \times N \]

where:

  • \( D \) is the diameter in meters (here, \( D = 200 \) mm = 0.2 m),
  • \( N \) is the rotation speed in revolutions per minute (rpm).

First, calculate the perimeter \( C \) of the grinding wheel:

\[ C = \pi \times D = \pi \times 0.2 \text{ m} \approx 0.6283 \text{ m} \]

Next, convert the rotation speed from rpm to revolutions per second (rps):

\[ N = 3000 \text{ r/min} = \frac{3000}{60} \text{ r/s} = 50 \text{ r/s} \]

Now calculate \( V \):

\[ V = C \times N = 0.6283 \text{ m} \times 50 \text{ r/s} \approx 31.415 \text{ m/s} \]

Step 2: Calculate the Useful Power Delivered to the Grinding Wheel

The useful power \( P_{useful} \) can be calculated using the formula:

\[ P_{useful} = F \times V \]

where \( F \) is the tangential force.

Here, \( F = 40 \text{ N} \):

\[ P_{useful} = 40 \text{ N} \times 31.415 \text{ m/s} \approx 1256.6 \text{ W} \]

Step 3: Calculate the Input Power of the Motor

Given the efficiency of the machine \( \eta = 72% = 0.72 \), we can calculate the input power \( P_{input} \):

\[ \eta = \frac{P_{useful}}{P_{input}} \]

Rearranging this gives:

\[ P_{input} = \frac{P_{useful}}{\eta} \]

Now substituting the values of \( P_{useful} \) and \( \eta \):

\[ P_{input} = \frac{1256.6 \text{ W}}{0.72} \approx 1741.6 \text{ W} \]

Conclusion

The input power of the motor is approximately 1741.6 W, or about 1.74 kW.