Asked by Maryo

The temperature in an electric oven is 160°C. The temperature at the outer surface in the kitchen is 50°C. The oven ( surface area = 1.6 m2) is insulated with material that has a thickness of 0.02 m and a thermal conductivity of 0.045 J/s.m.C°. (a) How much energy is used to operate the oven for six hours?(b) At the price of $0.1/kw-hr for electrical energy, what is the cost of operating the oven?

Answers

Answered by Maryo
Anyone Can answer this Please
Answered by drwls
Calculate the heat loss rate through the walls, using
P = (surface area)*k*(110C)/0.02 m
where k is the thermal conducticity

Convert watts (J/s) to kilowatts. Multiply the number of kW by 6h to get the number of kW-hr.

That is the energy required for steady state ooperation for 6 hours. There will be an additional amount required to heat up the oven - probably a few percent more, depending upon the specific heat.
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