The senior class at Hartford High School is planning their prom. They’ve narrowed the location down to two choices. The Regal Hotel charges, C , $500 for the ballroom rental fee and $75 per student, s , for the meal. The Greenhill Country Club charges, C , $1,000 for the ballroom rental fee and $65 per student, s , for the meal. Create a pair of linear equations that represent this real-world problem.(1 point)ResponsesRegal Hotel: C=75s+500; Greenhill Country Club: C=65s+1,000Regal Hotel: upper C equals 75 s plus 500 ; Greenhill Country Club: upper C equals 65 s plus 1,000Regal Hotel: C=1,000s+75; Greenhill Country Club: C=500s+65 Regal Hotel: upper C equals 1,000 s plus 75 ; Greenhill Country Club: upper C equals 500 s plus 65Regal Hotel: C=500s+75; Greenhill Country Club: C=1,000s+65 Regal Hotel: upper C equals 500 s plus 75 ; Greenhill Country Club: upper C equals 1,000 s plus 65Regal Hotel: C=75s+1,000; Greenhill Country Club: C=65s+500
1 answer
The correct pair of linear equations that represent the costs for the two venues, based on the information provided, can be formulated as follows:
For the Regal Hotel: \[ C = 75s + 500 \] This represents a $500 rental fee and $75 per student for the meal.
For the Greenhill Country Club: \[ C = 65s + 1,000 \] This represents a $1,000 rental fee and $65 per student for the meal.
Therefore, the answer is: Regal Hotel: C = 75s + 500; Greenhill Country Club: C = 65s + 1,000.
