Nen's suitcase is on a bench, the suitcase has a mass of 14 kg Nan accidentally knocks the suitcase Off the Bench and the suitcase Falls at a speed of 2.7 m per second how much kinetic energy does the suitcase have just before it hits the floor

Answer 1

To calculate the kinetic energy (KE) of the suitcase just before it hits the floor, you can use the kinetic energy formula:

$$KE=\frac{1}{2}m{v}^2$$

where:

• $m$ is the mass of the suitcase (in kilograms),
• $v$ is the velocity (in meters per second).

Given:

• $m=14,\text{kg}$
• $v=2.7,\text{m/s}$

Now, plug in the values:

$$KE=\frac{1}{2}\times 14,\text{kg}\times (2.7,\text{m/s}{)}^2$$

Calculating $(2.7,\text{m/s}{)}^2$:

$$(2.7{)}^2=7.29,{\text{m}}^2/{\text{s}}^2$$

Now substitute this back into the equation:

$$KE=\frac{1}{2}\times 14,\text{kg}\times 7.29,{\text{m}}^2/{\text{s}}^2$$

Calculating:

$$KE=7,\text{kg}\times 7.29,{\text{m}}^2/{\text{s}}^2$$ $$KE=51.03,\text{kg}\cdot {\text{m}}^2/{\text{s}}^2$$

Since $1,\text{kg}\cdot {\text{m}}^2/{\text{s}}^2=1,\text{J}$, we have:

$$KE\approx 51.03,\text{J}$$

Thus, the kinetic energy of the suitcase just before it hits the floor is approximately 51.03 joules.