Question

My Skibidi Team called The Sigma's won 2/9 of its games this seasons. If we lost 15 more games than we won, how many games did we play this season?

Answer 1

Let the total number of games played by your team be \( x \).

According to your information, you won \( \frac{2}{9} \) of your games. Therefore, the number of games you won is:

\[
\text{Games won} = \frac{2}{9} x
\]

You also mentioned that you lost 15 more games than you won, so the number of games lost is:

\[
\text{Games lost} = \text{Games won} + 15 = \frac{2}{9} x + 15
\]

The total number of games played is the sum of games won and games lost:

\[
x = \text{Games won} + \text{Games lost}
\]

Substituting the expressions for games won and lost into this equation gives:

\[
x = \frac{2}{9} x + \left( \frac{2}{9} x + 15 \right)
\]

This simplifies to:

\[
x = \frac{2}{9} x + \frac{2}{9} x + 15
\]
\[
x = \frac{4}{9} x + 15
\]

To isolate \( x \), subtract \( \frac{4}{9} x \) from both sides:

\[
x - \frac{4}{9} x = 15
\]
\[
\left(1 - \frac{4}{9}\right)x = 15
\]
\[
\frac{5}{9} x = 15
\]

Now, multiply both sides by \( \frac{9}{5} \) to solve for \( x \):

\[
x = 15 \cdot \frac{9}{5}
\]
\[
x = 27
\]

Therefore, the total number of games played this season is \( \boxed{27} \).

To verify:

- Games won: \( \frac{2}{9} \times 27 = 6 \)
- Games lost: \( 6 + 15 = 21 \)
- Total games: \( 6 + 21 = 27 \)

This confirms that our solution is correct!