Question
Using the genotypes and phenotypes provided from the iguana gene pool, which statement is NOT correct?
Responses
A Webbed feet is the recessive trait.Webbed feet is the recessive trait.
B WW x ww produces offspring with no webbing.WW x ww produces offspring with no webbing.
C 2 iguanas with no webbing could have an offspring with webbing.2 iguanas with no webbing could have an offspring with webbing.
D Crossing an iguana with webbed feet with one with no webbing would produce iguanas ALL with no webbing because this is the dominant trait.
Responses
A Webbed feet is the recessive trait.Webbed feet is the recessive trait.
B WW x ww produces offspring with no webbing.WW x ww produces offspring with no webbing.
C 2 iguanas with no webbing could have an offspring with webbing.2 iguanas with no webbing could have an offspring with webbing.
D Crossing an iguana with webbed feet with one with no webbing would produce iguanas ALL with no webbing because this is the dominant trait.
Answers
GPT-4o mini
To determine which statement is NOT correct, we need to analyze each statement about the genotypes and phenotypes related to webbed feet in iguanas.
1. **A. Webbed feet is the recessive trait.**
- If webbed feet are recessive, then the presence of webbed feet would only appear in the homozygous recessive genotype (ww).
2. **B. WW x ww produces offspring with no webbing.**
- If WW (homozygous dominant) is crossed with ww (homozygous recessive), all offspring will be Ww (heterozygous) and will display the dominant phenotype, which means they would not have webbed feet.
3. **C. 2 iguanas with no webbing could have an offspring with webbing.**
- If both parents are homozygous for no webbing (WW), they will not produce offspring with webbing. However, if both are heterozygous (Ww), they can produce offspring with webbing (ww). Without specific genotype information, we cannot definitively claim this to be correct or incorrect.
4. **D. Crossing an iguana with webbed feet with one with no webbing would produce iguanas ALL with no webbing because this is the dominant trait.**
- If the iguana with webbed feet is homozygous dominant (WW) and the one with no webbing is homozygous recessive (ww), all offspring will be Ww and will not have webbed feet, supporting this statement.
Considering the analysis, **statement B** is incorrect as WW x ww would produce offspring that all exhibit the dominant trait (no webbing), not the recessive trait (webbed feet).
Therefore, the answer is: **B. WW x ww produces offspring with no webbing.**
1. **A. Webbed feet is the recessive trait.**
- If webbed feet are recessive, then the presence of webbed feet would only appear in the homozygous recessive genotype (ww).
2. **B. WW x ww produces offspring with no webbing.**
- If WW (homozygous dominant) is crossed with ww (homozygous recessive), all offspring will be Ww (heterozygous) and will display the dominant phenotype, which means they would not have webbed feet.
3. **C. 2 iguanas with no webbing could have an offspring with webbing.**
- If both parents are homozygous for no webbing (WW), they will not produce offspring with webbing. However, if both are heterozygous (Ww), they can produce offspring with webbing (ww). Without specific genotype information, we cannot definitively claim this to be correct or incorrect.
4. **D. Crossing an iguana with webbed feet with one with no webbing would produce iguanas ALL with no webbing because this is the dominant trait.**
- If the iguana with webbed feet is homozygous dominant (WW) and the one with no webbing is homozygous recessive (ww), all offspring will be Ww and will not have webbed feet, supporting this statement.
Considering the analysis, **statement B** is incorrect as WW x ww would produce offspring that all exhibit the dominant trait (no webbing), not the recessive trait (webbed feet).
Therefore, the answer is: **B. WW x ww produces offspring with no webbing.**