Question

Which of the following ordered pairs is in the solution set for y=8x−1
y
=
8
x
−
1
?(1 point)
Responses

(2,15)
(
2
,
15
)
left parenthesis 2 comma 15 right parenthesis

(2,82)
(
2
,
82
)
left parenthesis 2 comma 82 right parenthesis

(2,81)
(
2
,
81
)
left parenthesis 2 comma 81 right parenthesis

(2,16)

Answer 1

To determine which ordered pair is in the solution set of the equation \( y = 8x - 1 \), we need to substitute the value of \( x \) from each ordered pair into the equation and check if the resulting \( y \) value matches the \( y \) value in the ordered pair.

Let's evaluate each option:

1. For \( (2, 15) \):
\[
y = 8(2) - 1 = 16 - 1 = 15
\]
This matches the given \( y \) value.

2. For \( (2, 82) \):
\[
y = 8(2) - 1 = 16 - 1 = 15
\]
This does not match.

3. For \( (2, 81) \):
\[
y = 8(2) - 1 = 16 - 1 = 15
\]
This does not match.

4. For \( (2, 16) \):
\[
y = 8(2) - 1 = 16 - 1 = 15
\]
This does not match.

The only ordered pair that is in the solution set for \( y = 8x - 1 \) is \( (2, 15) \).