If the side opposite a 60-degree angle in a 30-60-90 right triangle is 73–√ cm

long, how long is the hypotenuse?(1 point)

1 answer

In a 30-60-90 right triangle, the sides have a specific ratio:

  • The side opposite the 30-degree angle is \( x \).
  • The side opposite the 60-degree angle is \( x\sqrt{3} \).
  • The hypotenuse is \( 2x \).

From the problem, we know that the side opposite the 60-degree angle is \( 73 - \sqrt{cm} \) long. According to the ratio, this side can be expressed as:

\[ x\sqrt{3} = 73 - \sqrt{cm} \]

To find \( x \), we can isolate \( x \):

\[ x = \frac{73 - \sqrt{cm}}{\sqrt{3}} \]

Next, the hypotenuse \( c \) of the triangle can be calculated as follows:

\[ c = 2x = 2 \left( \frac{73 - \sqrt{cm}}{\sqrt{3}} \right) = \frac{2(73 - \sqrt{cm})}{\sqrt{3}} \]

Thus, the length of the hypotenuse is:

\[ c = \frac{146 - 2\sqrt{cm}}{\sqrt{3}} \text{ cm} \]

So, that is the length of the hypotenuse in the triangle.