Question
Joe pushes a box up an inclined plane with an efficiency of 48%. If 388 joules of energy went into moving the box, how much energy did Joe put into the inclined plane?(1 point) Responses 186.2 Joules 186.2 Joules 808.3 Joules 808.3 Joules 436 Joules 436 Joules 18,624 Joules 18,624 Joules
Answers
GPT-4o mini
Efficiency is defined as the ratio of useful output energy to the input energy, expressed as a percentage. The formula for efficiency can be written as:
\[
\text{Efficiency} = \left( \frac{\text{Useful Output Energy}}{\text{Input Energy}} \right) \times 100
\]
In this case, we know that Joe's efficiency is 48% and the useful output energy (energy used to move the box) is 388 joules. We can rearrange the formula to find the input energy (the energy Joe put in):
\[
\text{Input Energy} = \frac{\text{Useful Output Energy}}{\text{Efficiency}}
\]
Since the efficiency is in percentage, we need to convert it to a decimal:
\[
\text{Efficiency} = 48\% = 0.48
\]
Now we can calculate the input energy:
\[
\text{Input Energy} = \frac{388 \text{ joules}}{0.48} \approx 808.3 \text{ joules}
\]
Thus, Joe put approximately **808.3 joules** of energy into the inclined plane.
The correct response is **808.3 Joules**.
\[
\text{Efficiency} = \left( \frac{\text{Useful Output Energy}}{\text{Input Energy}} \right) \times 100
\]
In this case, we know that Joe's efficiency is 48% and the useful output energy (energy used to move the box) is 388 joules. We can rearrange the formula to find the input energy (the energy Joe put in):
\[
\text{Input Energy} = \frac{\text{Useful Output Energy}}{\text{Efficiency}}
\]
Since the efficiency is in percentage, we need to convert it to a decimal:
\[
\text{Efficiency} = 48\% = 0.48
\]
Now we can calculate the input energy:
\[
\text{Input Energy} = \frac{388 \text{ joules}}{0.48} \approx 808.3 \text{ joules}
\]
Thus, Joe put approximately **808.3 joules** of energy into the inclined plane.
The correct response is **808.3 Joules**.