To determine whether the point (2, 2) is a solution to each of the inequalities, we can substitute \(x = 2\) and \(y = 2\) into each inequality and check their validity.
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For the inequality \(y < -2x + 1\):
Substitute \(x = 2\) and \(y = 2\): \[ 2 < -2(2) + 1 \] \[ 2 < -4 + 1 \] \[ 2 < -3 \quad \text{(False)} \]
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For the inequality \(y \ge 3x - 2\):
Substitute \(x = 2\) and \(y = 2\): \[ 2 \ge 3(2) - 2 \] \[ 2 \ge 6 - 2 \] \[ 2 \ge 4 \quad \text{(False)} \]
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For the inequality \(y > x - 1\):
Substitute \(x = 2\) and \(y = 2\): \[ 2 > 2 - 1 \] \[ 2 > 1 \quad \text{(True)} \]
The only inequality for which (2, 2) is a solution is:
- \(y > x - 1\)
Thus, the answer to which inequalities have (2, 2) as a solution is:
- \(y > x - 1\)