To solve the given system of equations, I'll guide you through the steps:
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Choose the best method to solve by looking at the way the equations are set up for you:
- Elimination method (This method simplifies the calculations since the coefficients of \( y \) can be worked with easily).
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Using the best method, how could you get the x variables to cancel out?
- Multiply the first equation by 2, so that the coefficients in front of \( x \) will be the same in both equations.
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After you complete step 2, what would your top equation be?
- \( 6x + 8y = 96 \)
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Line them up and add the equations together to get this equation.
- \( (6x + 8y) + (6x + 2y) = 96 + 60 \)
This simplifies to: - \( 12x + 10y = 156 \)
- \( (6x + 8y) + (6x + 2y) = 96 + 60 \)
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Solve for y.
- From the original set of equations, you could isolate one variable after adding: Combine the similar terms: \( 10y = 156 - 12x \)
Next, choose to isolate \( y \):
- \( 10y = 156 - 12x \)
To simplify, divide each term by 10: - \( y = \frac{156 - 12x}{10} \)
- \( y = 15.6 - 1.2x \)
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Solve for x.
- Use one of the original equations, substituting \( y \) back in: From the original equation \( 3x + 4y = 48 \), Substitute \( y \):
- \( 3x + 4(15.6 - 1.2x) = 48 \)
- \( 3x + 62.4 - 4.8x = 48 \) Combine like terms:
- \( -1.8x + 62.4 = 48 \) Solve for \( x \):
- \( -1.8x = 48 - 62.4 \)
- \( -1.8x = -14.4 \)
- \( x = 8 \)
Finally, using either original equation to solve for \( y \):
- Substitute \( x = 8 \) back into \( 3x + 4y = 48 \):
- \( 3(8) + 4y = 48 \)
- \( 24 + 4y = 48 \)
- \( 4y = 48 - 24 \)
- \( 4y = 24 \)
- \( y = 6 \)
Thus, the solution to the system of equations is:
- \( x = 8 \)
- \( y = 6 \)