Question
Which substance combines with iron in the presence of water to form rust?(1 point)
Responses
carbon dioxide
carbon dioxide
acid
acid
nitrogen
nitrogen
oxygen
Which process is most likely responsible for the formation of limestone caves?(1 point)
Responses
abrasion
abrasion
carbonation
carbonation
hydrolysis
hydrolysis
oxidation
oxidation
Which option best describes hydrolysis?(1 point)
Responses
oxygen in water combining chemically with substances in rock
oxygen in water combining chemically with substances in rock
water reacting chemically with minerals in rock
water reacting chemically with minerals in rock
carbon dioxide reacting with water to form an acid that dissolves minerals in rock
carbon dioxide reacting with water to form an acid that dissolves minerals in rock
hydrogen in water combining chemically with substances in rock
hydrogen in water combining chemically with substances in rock
Which type of region would be most likely to support chemical weathering?(1 point)
Responses
a desert region with very little rain
a desert region with very little rain
a temperate region with warm summers and cold winters
a temperate region with warm summers and cold winters
a tropical region that is hot and humid all year long
a tropical region that is hot and humid all year long
a polar region that is cold and dry all year long
Responses
carbon dioxide
carbon dioxide
acid
acid
nitrogen
nitrogen
oxygen
Which process is most likely responsible for the formation of limestone caves?(1 point)
Responses
abrasion
abrasion
carbonation
carbonation
hydrolysis
hydrolysis
oxidation
oxidation
Which option best describes hydrolysis?(1 point)
Responses
oxygen in water combining chemically with substances in rock
oxygen in water combining chemically with substances in rock
water reacting chemically with minerals in rock
water reacting chemically with minerals in rock
carbon dioxide reacting with water to form an acid that dissolves minerals in rock
carbon dioxide reacting with water to form an acid that dissolves minerals in rock
hydrogen in water combining chemically with substances in rock
hydrogen in water combining chemically with substances in rock
Which type of region would be most likely to support chemical weathering?(1 point)
Responses
a desert region with very little rain
a desert region with very little rain
a temperate region with warm summers and cold winters
a temperate region with warm summers and cold winters
a tropical region that is hot and humid all year long
a tropical region that is hot and humid all year long
a polar region that is cold and dry all year long
Answers
Answered by
GPT-4o mini
Here are the answers to your questions:
1. **Which substance combines with iron in the presence of water to form rust?**
- **Answer:** **oxygen**
2. **Which process is most likely responsible for the formation of limestone caves?**
- **Answer:** **carbonation**
3. **Which option best describes hydrolysis?**
- **Answer:** **water reacting chemically with minerals in rock**
4. **Which type of region would be most likely to support chemical weathering?**
- **Answer:** **a tropical region that is hot and humid all year long**
If you have any more questions or need further clarification, feel free to ask!
1. **Which substance combines with iron in the presence of water to form rust?**
- **Answer:** **oxygen**
2. **Which process is most likely responsible for the formation of limestone caves?**
- **Answer:** **carbonation**
3. **Which option best describes hydrolysis?**
- **Answer:** **water reacting chemically with minerals in rock**
4. **Which type of region would be most likely to support chemical weathering?**
- **Answer:** **a tropical region that is hot and humid all year long**
If you have any more questions or need further clarification, feel free to ask!
Answer
Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other is already filled with 10 gallons, and it is continuing to fill at a rate of 4 gallons per minute. Write an equation to show when the two vats will have an equal amount of liquid. Use x as your variable. (1 point)
A yoga studio has two participation plans. For the first plan, the cost is $8 per visit. For the second plan, the cost is $40 per month, and $2 per visit. Write an equation to show the number of visits per month that it would take for the two plans to be equal. Use x as your variable.(1 point)
A yoga studio has two participation plans. For the first plan, the cost is $8 per visit. For the second plan, the cost is $40 per month, and $2 per visit. Write an equation to show the number of visits per month that it would take for the two plans to be equal. Use x as your variable.(1 point)
Answered by
GPT-4o mini
Sure! Here are the equations for both scenarios:
1. **Filling Two Vats:**
- Let \( x \) be the number of minutes.
- The first vat is empty and fills at a rate of 6 gallons per minute:
\[
\text{Amount in first vat} = 6x
\]
- The second vat starts with 10 gallons and fills at a rate of 4 gallons per minute:
\[
\text{Amount in second vat} = 10 + 4x
\]
- To find when the two vats have an equal amount of liquid, set the two expressions equal to each other:
\[
6x = 10 + 4x
\]
2. **Yoga Studio Participation Plans:**
- Let \( x \) be the number of visits per month.
- The cost for the first plan is \( 8 \times x \):
\[
\text{Cost for Plan 1} = 8x
\]
- The cost for the second plan is a fixed fee of $40 plus $2 for each visit:
\[
\text{Cost for Plan 2} = 40 + 2x
\]
- To find when the costs are equal, set the two cost expressions equal to each other:
\[
8x = 40 + 2x
\]
Now you have the equations for both scenarios! If you need further assistance or explanations, let me know!
1. **Filling Two Vats:**
- Let \( x \) be the number of minutes.
- The first vat is empty and fills at a rate of 6 gallons per minute:
\[
\text{Amount in first vat} = 6x
\]
- The second vat starts with 10 gallons and fills at a rate of 4 gallons per minute:
\[
\text{Amount in second vat} = 10 + 4x
\]
- To find when the two vats have an equal amount of liquid, set the two expressions equal to each other:
\[
6x = 10 + 4x
\]
2. **Yoga Studio Participation Plans:**
- Let \( x \) be the number of visits per month.
- The cost for the first plan is \( 8 \times x \):
\[
\text{Cost for Plan 1} = 8x
\]
- The cost for the second plan is a fixed fee of $40 plus $2 for each visit:
\[
\text{Cost for Plan 2} = 40 + 2x
\]
- To find when the costs are equal, set the two cost expressions equal to each other:
\[
8x = 40 + 2x
\]
Now you have the equations for both scenarios! If you need further assistance or explanations, let me know!
Answer
A diner makes vanilla milkshakes and chocolate milkshakes. The vanilla milkshake machine has a 300-cup capacity, and sells 15 cups per day. The chocolate milkshake machine has a 280-cup capacity, and sells 20 cups per day. Write an equation to show when the two machines will have the same amount of milkshake left. Use x
as your variable.
(1 point)Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid?(1 point)
as your variable.
(1 point)Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid?(1 point)
Answered by
GPT-4o mini
Sure! Here are the equations for both scenarios:
1. **Diner with Vanilla and Chocolate Milkshakes:**
- Let \( x \) be the number of days.
- The vanilla milkshake machine starts with a capacity of 300 cups and sells 15 cups per day:
\[
\text{Amount left in vanilla machine} = 300 - 15x
\]
- The chocolate milkshake machine starts with a capacity of 280 cups and sells 20 cups per day:
\[
\text{Amount left in chocolate machine} = 280 - 20x
\]
- To find when the two machines will have the same amount of milkshake left, set the two expressions equal to each other:
\[
300 - 15x = 280 - 20x
\]
2. **Filling Two Vats:**
- Let \( x \) be the number of minutes.
- The first vat is empty and fills at a rate of 6 gallons per minute:
\[
\text{Amount in first vat} = 6x
\]
- The second vat already contains 28 gallons and fills at a rate of 4 gallons per minute:
\[
\text{Amount in second vat} = 28 + 4x
\]
- To find when the two vats have the same amount of liquid, set the two expressions equal to each other:
\[
6x = 28 + 4x
\]
Now you have the equations for both scenarios! If you need further assistance, feel free to ask!
1. **Diner with Vanilla and Chocolate Milkshakes:**
- Let \( x \) be the number of days.
- The vanilla milkshake machine starts with a capacity of 300 cups and sells 15 cups per day:
\[
\text{Amount left in vanilla machine} = 300 - 15x
\]
- The chocolate milkshake machine starts with a capacity of 280 cups and sells 20 cups per day:
\[
\text{Amount left in chocolate machine} = 280 - 20x
\]
- To find when the two machines will have the same amount of milkshake left, set the two expressions equal to each other:
\[
300 - 15x = 280 - 20x
\]
2. **Filling Two Vats:**
- Let \( x \) be the number of minutes.
- The first vat is empty and fills at a rate of 6 gallons per minute:
\[
\text{Amount in first vat} = 6x
\]
- The second vat already contains 28 gallons and fills at a rate of 4 gallons per minute:
\[
\text{Amount in second vat} = 28 + 4x
\]
- To find when the two vats have the same amount of liquid, set the two expressions equal to each other:
\[
6x = 28 + 4x
\]
Now you have the equations for both scenarios! If you need further assistance, feel free to ask!
Answer
Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point
Movie Theatre A has a popcorn machine with a 100-gallon capacity, and sells 3 gallons of popcorn per hour. Movie Theatre B has a popcorn machine with a 150-gallon capacity, and sells 5 gallons of popcorn per hour. Write an equation to show when the two popcorn machines will have the same amount of popcorn left. Use x as your variable.(1 point)
Responses
An ice cream shop makes vanilla and chocolate ice cream. The vanilla ice cream machine has a 180-cup capacity, and it sells 20 cups per day. The chocolate ice cream machine has a 140-cup capacity, and it sells 16 cups per day. Write and solve an equation to show when the two machines will have the same amount of ice cream left.(1 point)
Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Responses
Movie Theatre A has a popcorn machine with a 120-gallon capacity. It sells 7 gallons of popcorn per hour. Movie Theatre B has a popcorn machine with a 150-gallon capacity. It sells 9 gallons of popcorn per hour. Write and solve an equation to show when the two popcorn machines will have the same amount of popcorn left.(1 point)
Movie Theatre A has a popcorn machine with a 100-gallon capacity, and sells 3 gallons of popcorn per hour. Movie Theatre B has a popcorn machine with a 150-gallon capacity, and sells 5 gallons of popcorn per hour. Write an equation to show when the two popcorn machines will have the same amount of popcorn left. Use x as your variable.(1 point)
Responses
An ice cream shop makes vanilla and chocolate ice cream. The vanilla ice cream machine has a 180-cup capacity, and it sells 20 cups per day. The chocolate ice cream machine has a 140-cup capacity, and it sells 16 cups per day. Write and solve an equation to show when the two machines will have the same amount of ice cream left.(1 point)
Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Responses
Movie Theatre A has a popcorn machine with a 120-gallon capacity. It sells 7 gallons of popcorn per hour. Movie Theatre B has a popcorn machine with a 150-gallon capacity. It sells 9 gallons of popcorn per hour. Write and solve an equation to show when the two popcorn machines will have the same amount of popcorn left.(1 point)
Answered by
GPT-4o mini
Here are the equations for each of the scenarios you've described:
1. **Two Machines Filling Cans of Soup:**
- Let \( x \) be the number of minutes.
- The first machine has already filled 180 cans and fills at a rate of 15 cans per minute:
\[
\text{Cans filled by machine 1} = 180 + 15x
\]
- The second machine has already filled 210 cans and fills at a rate of 12 cans per minute:
\[
\text{Cans filled by machine 2} = 210 + 12x
\]
- To find when both machines have filled the same number of cans:
\[
180 + 15x = 210 + 12x
\]
2. **Popcorn Machines at Movie Theatres:**
- Let \( x \) be the number of hours.
- Movie Theatre A has a 100-gallon capacity and sells 3 gallons of popcorn per hour:
\[
\text{Amount of popcorn left in Theatre A} = 100 - 3x
\]
- Movie Theatre B has a 150-gallon capacity and sells 5 gallons of popcorn per hour:
\[
\text{Amount of popcorn left in Theatre B} = 150 - 5x
\]
- To find when both machines have the same amount of popcorn left:
\[
100 - 3x = 150 - 5x
\]
3. **Ice Cream Machines at an Ice Cream Shop:**
- Let \( x \) be the number of days.
- The vanilla ice cream machine has a 180-cup capacity and sells 20 cups per day:
\[
\text{Amount of vanilla left} = 180 - 20x
\]
- The chocolate ice cream machine has a 140-cup capacity and sells 16 cups per day:
\[
\text{Amount of chocolate left} = 140 - 16x
\]
- To find when both machines have the same amount of ice cream left:
\[
180 - 20x = 140 - 16x
\]
4. **Another Two Machines Filling Cans of Soup:**
- Let \( x \) be the number of minutes.
- The first machine has already filled 92 cans and fills at a rate of 16 cans per minute:
\[
\text{Cans filled by machine 1} = 92 + 16x
\]
- The second machine has already filled 104 cans and fills at a rate of 13 cans per minute:
\[
\text{Cans filled by machine 2} = 104 + 13x
\]
- To find when both machines have filled the same number of cans:
\[
92 + 16x = 104 + 13x
\]
5. **Popcorn Machines at Movie Theatres:**
- Let \( x \) be the number of hours.
- Movie Theatre A has a 120-gallon capacity and sells 7 gallons per hour:
\[
\text{Amount of popcorn left in Theatre A} = 120 - 7x
\]
- Movie Theatre B has a 150-gallon capacity and sells 9 gallons of popcorn per hour:
\[
\text{Amount of popcorn left in Theatre B} = 150 - 9x
\]
- To find when both machines have the same amount of popcorn left:
\[
120 - 7x = 150 - 9x
\]
You can solve each of these equations as needed. If you would like help with solving any specific equation, please let me know!
1. **Two Machines Filling Cans of Soup:**
- Let \( x \) be the number of minutes.
- The first machine has already filled 180 cans and fills at a rate of 15 cans per minute:
\[
\text{Cans filled by machine 1} = 180 + 15x
\]
- The second machine has already filled 210 cans and fills at a rate of 12 cans per minute:
\[
\text{Cans filled by machine 2} = 210 + 12x
\]
- To find when both machines have filled the same number of cans:
\[
180 + 15x = 210 + 12x
\]
2. **Popcorn Machines at Movie Theatres:**
- Let \( x \) be the number of hours.
- Movie Theatre A has a 100-gallon capacity and sells 3 gallons of popcorn per hour:
\[
\text{Amount of popcorn left in Theatre A} = 100 - 3x
\]
- Movie Theatre B has a 150-gallon capacity and sells 5 gallons of popcorn per hour:
\[
\text{Amount of popcorn left in Theatre B} = 150 - 5x
\]
- To find when both machines have the same amount of popcorn left:
\[
100 - 3x = 150 - 5x
\]
3. **Ice Cream Machines at an Ice Cream Shop:**
- Let \( x \) be the number of days.
- The vanilla ice cream machine has a 180-cup capacity and sells 20 cups per day:
\[
\text{Amount of vanilla left} = 180 - 20x
\]
- The chocolate ice cream machine has a 140-cup capacity and sells 16 cups per day:
\[
\text{Amount of chocolate left} = 140 - 16x
\]
- To find when both machines have the same amount of ice cream left:
\[
180 - 20x = 140 - 16x
\]
4. **Another Two Machines Filling Cans of Soup:**
- Let \( x \) be the number of minutes.
- The first machine has already filled 92 cans and fills at a rate of 16 cans per minute:
\[
\text{Cans filled by machine 1} = 92 + 16x
\]
- The second machine has already filled 104 cans and fills at a rate of 13 cans per minute:
\[
\text{Cans filled by machine 2} = 104 + 13x
\]
- To find when both machines have filled the same number of cans:
\[
92 + 16x = 104 + 13x
\]
5. **Popcorn Machines at Movie Theatres:**
- Let \( x \) be the number of hours.
- Movie Theatre A has a 120-gallon capacity and sells 7 gallons per hour:
\[
\text{Amount of popcorn left in Theatre A} = 120 - 7x
\]
- Movie Theatre B has a 150-gallon capacity and sells 9 gallons of popcorn per hour:
\[
\text{Amount of popcorn left in Theatre B} = 150 - 9x
\]
- To find when both machines have the same amount of popcorn left:
\[
120 - 7x = 150 - 9x
\]
You can solve each of these equations as needed. If you would like help with solving any specific equation, please let me know!