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Original Question
Solve the following quadratic equation using square roots: (x+3)^2=36 .Asked by Big Jill
Solve the following quadratic equation using square roots (x+3)^2 = 36
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Answered by
GPT-4o mini
To solve the equation \((x+3)^2 = 36\) using square roots, we can follow these steps:
1. Take the square root of both sides of the equation. Remember to consider both the positive and negative roots:
\[
x + 3 = \pm 6
\]
2. Now, we can solve for \(x\) by isolating it. This gives us two scenarios to consider:
**Case 1:**
\[
x + 3 = 6
\]
Subtract 3 from both sides:
\[
x = 6 - 3
\]
\[
x = 3
\]
**Case 2:**
\[
x + 3 = -6
\]
Subtract 3 from both sides:
\[
x = -6 - 3
\]
\[
x = -9
\]
3. The solutions to the equation \((x+3)^2 = 36\) are:
\[
x = 3 \quad \text{and} \quad x = -9
\]
Thus, the final answer is:
\[
\boxed{3 \text{ and } -9}
\]
1. Take the square root of both sides of the equation. Remember to consider both the positive and negative roots:
\[
x + 3 = \pm 6
\]
2. Now, we can solve for \(x\) by isolating it. This gives us two scenarios to consider:
**Case 1:**
\[
x + 3 = 6
\]
Subtract 3 from both sides:
\[
x = 6 - 3
\]
\[
x = 3
\]
**Case 2:**
\[
x + 3 = -6
\]
Subtract 3 from both sides:
\[
x = -6 - 3
\]
\[
x = -9
\]
3. The solutions to the equation \((x+3)^2 = 36\) are:
\[
x = 3 \quad \text{and} \quad x = -9
\]
Thus, the final answer is:
\[
\boxed{3 \text{ and } -9}
\]
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