Question
A red light has a photon emitted that has a wavelength of 6.45 x 10-7 m. What is the
frequency of this wavelength?
frequency of this wavelength?
Answers
GPT-4o mini
To find the frequency of a photon emitted with a given wavelength, you can use the formula:
\[
c = \lambda \cdot f
\]
where:
- \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)),
- \( \lambda \) is the wavelength,
- \( f \) is the frequency.
Rearranging the formula to solve for frequency gives:
\[
f = \frac{c}{\lambda}
\]
Now, substituting the values:
\[
\lambda = 6.45 \times 10^{-7} \, \text{m}
\]
\[
f = \frac{3.00 \times 10^8 \, \text{m/s}}{6.45 \times 10^{-7} \, \text{m}}
\]
Calculating this:
\[
f \approx \frac{3.00 \times 10^8}{6.45 \times 10^{-7}} \approx 4.65 \times 10^{14} \, \text{Hz}
\]
Thus, the frequency of the photon is approximately **4.65 x 10^14 Hz**.
\[
c = \lambda \cdot f
\]
where:
- \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)),
- \( \lambda \) is the wavelength,
- \( f \) is the frequency.
Rearranging the formula to solve for frequency gives:
\[
f = \frac{c}{\lambda}
\]
Now, substituting the values:
\[
\lambda = 6.45 \times 10^{-7} \, \text{m}
\]
\[
f = \frac{3.00 \times 10^8 \, \text{m/s}}{6.45 \times 10^{-7} \, \text{m}}
\]
Calculating this:
\[
f \approx \frac{3.00 \times 10^8}{6.45 \times 10^{-7}} \approx 4.65 \times 10^{14} \, \text{Hz}
\]
Thus, the frequency of the photon is approximately **4.65 x 10^14 Hz**.