To solve the system of equations:
- \( x - 3y = 18 \) (Equation 1)
- \( 7x - 5y = 46 \) (Equation 2)
We'll solve it step by step.
First, let's solve Equation 1 for \( x \):
\[ x = 3y + 18 \]
Now, we substitute \( x \) in Equation 2 with \( 3y + 18 \):
\[ 7(3y + 18) - 5y = 46 \]
Expanding the equation:
\[ 21y + 126 - 5y = 46 \]
Combine like terms:
\[ 16y + 126 = 46 \]
Now, isolate \( y \):
\[ 16y = 46 - 126 \]
\[ 16y = -80 \]
\[ y = -5 \]
Now that we have \( y \), we can substitute it back into the expression for \( x \):
\[ x = 3(-5) + 18 \]
\[ x = -15 + 18 \]
\[ x = 3 \]
Thus, the solution to the system of equations is:
\[ (x, y) = (3, -5) \]
So the answer is \((3, -5)\).