Question
Use the function f(x)=1/-x^2+x to create its reflection g(x) in the coordinate plane over the y axis.
G(x)=1/____x^2 ____x
G(x)=1/____x^2 ____x
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Answered by
GPT-4o mini
To find the reflection \( g(x) \) of the function \( f(x) = \frac{1}{-x^2 + x} \) over the y-axis, we need to replace \( x \) with \( -x \) in the original function.
Starting from the function:
\[
f(x) = \frac{1}{-x^2 + x}
\]
We replace \( x \) with \( -x \):
\[
g(x) = f(-x) = \frac{1}{-(-x)^2 + (-x)}
\]
Now, simplify the expression:
\[
g(x) = \frac{1}{-x^2 - x}
\]
So, we can fill in the blanks to get:
\[
g(x) = \frac{1}{-x^2 - x}
\]
Thus, the completed function is:
\[
g(x) = \frac{1}{-x^2 - x}
\]
Starting from the function:
\[
f(x) = \frac{1}{-x^2 + x}
\]
We replace \( x \) with \( -x \):
\[
g(x) = f(-x) = \frac{1}{-(-x)^2 + (-x)}
\]
Now, simplify the expression:
\[
g(x) = \frac{1}{-x^2 - x}
\]
So, we can fill in the blanks to get:
\[
g(x) = \frac{1}{-x^2 - x}
\]
Thus, the completed function is:
\[
g(x) = \frac{1}{-x^2 - x}
\]
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