Asked by Naso
In a physics lab experiment, a spring clamped to the table shoots a 22 g ball horizontally. When the spring is compressed 22 cm, the ball travels horizontally 5.2 m and lands on the floor 1.3 m below the point at which it left the spring.
What is the spring constant?
What is the spring constant?
Answers
Answered by
drwls
The time to fall 1.3 m is given by the equation
1.3 m = (g/2) t^2
t = 0.515 s
The horizontal velocity component, which equals the initial velocity, is
Vo = 5.2 m/0.515s = 10.1 m/s
Fot the spring constant k, solve
(1/2) k(0.22)^2 = (1/2) M Vo^2
k = M Vo^2/(0.22 m)
1.3 m = (g/2) t^2
t = 0.515 s
The horizontal velocity component, which equals the initial velocity, is
Vo = 5.2 m/0.515s = 10.1 m/s
Fot the spring constant k, solve
(1/2) k(0.22)^2 = (1/2) M Vo^2
k = M Vo^2/(0.22 m)
Answered by
bob
10.2
Answered by
dj
n a physics lab experiment, a spring clamped to the table shoots a 21 g ball horizontally. When the spring is compressed 20 cm , the ball travels horizontally 5.2 m and lands on the floor 1.5 m below the point at which it left the spring.
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