Question

A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105
gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
Responses

5.478×106
lb.
5 point 4 7 8 times 10 to the 6th power lb.

54.78×105
lb.
54 point 7 8 times 10 to the 5th power lb.

5.478×105
lb.
5 point 4 7 8 times 10 to the 5th power lb.

54.78×106
lb.

Answer 1

To find the approximate weight of the water in an Olympic-sized swimming pool, you can multiply the number of gallons the pool holds by the weight of a gallon of water.

Given:
- Weight of water per gallon = 8.3 lb
- Volume of the Olympic-sized swimming pool = \(6.6 \times 10^5\) gallons

Now, calculate the total weight:

\[
\text{Weight} = \text{Volume} \times \text{Weight per gallon} = (6.6 \times 10^5 \, \text{gallons}) \times (8.3 \, \text{lb/gallon})
\]

Calculating this:

\[
\text{Weight} = 6.6 \times 8.3 \times 10^5 \, \text{lb}
\]

Calculating \(6.6 \times 8.3\):

\[
6.6 \times 8.3 = 54.78
\]

Now substitute back into the equation:

\[
\text{Weight} = 54.78 \times 10^5 \, \text{lb}
\]

Now convert \(54.78 \times 10^5\) into scientific notation. \(54.78\) can be rewritten as \(5.478 \times 10^1\):

\[
54.78 \times 10^5 = 5.478 \times 10^1 \times 10^5 = 5.478 \times 10^{6}
\]

Thus, the approximate weight of the water in an Olympic-sized swimming pool is:

\[
\boxed{5.478 \times 10^6 \text{ lb}}
\]