To factor the quadratic expression \(3x^2 - 13x - 10\), you would generally follow these steps:
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Identify \(a\), \(b\), and \(c\) in the quadratic \(ax^2 + bx + c\). Here, \(a = 3\), \(b = -13\), and \(c = -10\).
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Multiply \(a\) and \(c\). Calculate \(3 \times -10 = -30\).
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Find two numbers that multiply to \(-30\) (the product from step 2) and add to \(-13\) (the value of \(b\)). The numbers are \(-15\) and \(2\).
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Rewrite the middle term \(-13x\) using the two numbers found in step 3. Rewrite \(3x^2 - 15x + 2x - 10\).
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Factor by grouping. Group the first two terms and the last two terms: \((3x^2 - 15x) + (2x - 10)\).
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Factor out the common factors from each group: \(3x(x - 5) + 2(x - 5)\).
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Factor out the common binomial: \((x - 5)(3x + 2)\).
So, in order, the steps to factor \(3x^2 - 13x - 10\) are as follows:
- Identify \(a\), \(b\), and \(c\).
- Multiply \(a\) and \(c\).
- Find two numbers that multiply to \(-30\) and add to \(-13\).
- Rewrite the middle term using those two numbers.
- Factor by grouping.
- Factor out the common factors from each group.
- Factor out the common binomial.
If you need to arrange the provided responses according to these steps, please provide those responses and I can help you arrange them correctly!