To determine the total mass of the reactants in the reaction between iron chloride (FeCl₃) and water (H₂O), you would need to know the number of moles of each reactant involved in the reaction as well as the atomic masses of the elements in question (iron, chlorine, hydrogen, and oxygen).
Assuming a common reaction between iron chloride and water, we can consider the equation:
\[ \text{FeCl}_3 + 3 \text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3 \text{HCl} \]
To calculate the total mass of the reactants, here's a breakdown of the components:
-
Iron Chloride (FeCl₃):
- Iron (Fe): Atomic mass = 55.85 g/mol
- Chlorine (Cl): Atomic mass = 35.45 g/mol
- Formula for FeCl₃: 1 Fe + 3 Cl
Total mass of FeCl₃: \[ \text{Mass of FeCl}_3 = (1 \times 55.85) + (3 \times 35.45) = 55.85 + 106.35 = 162.20 \text{ g/mol} \]
-
Water (H₂O):
- Hydrogen (H): Atomic mass = 1.01 g/mol
- Oxygen (O): Atomic mass = 16.00 g/mol
- Formula for H₂O: 2 H + 1 O
Total mass of H₂O: \[ \text{Mass of H}_2\text{O} = (2 \times 1.01) + (1 \times 16.00) = 2.02 + 16.00 = 18.02 \text{ g/mol} \]
Now, if we consider the reaction consumes 1 mole of FeCl₃ and 3 moles of H₂O:
- Total mass of the reactants: \[ \text{Total mass} = \text{mass of 1 mol of FeCl}_3 + \text{mass of 3 mol of H}_2\text{O} \] \[ \text{Total mass} = 162.20 \text{ g/mol} + (3 \times 18.02 \text{ g/mol}) = 162.20 \text{ g/mol} + 54.06 \text{ g/mol} = 216.26 \text{ g/mol} \]
Therefore, the total mass of the reactants is 216.26 grams per mole for the complete reaction involving 1 mole of iron chloride and 3 moles of water.