Question
Rhombus QRST has diagonal lines QS¯¯¯¯¯¯¯ and RT¯¯¯¯¯¯¯ that intersect at U. If QS¯¯¯¯¯¯¯=30 and RT¯¯¯¯¯¯¯=16, what is the length of one of the sides of the rhombus?(1 point)
Responses
46
46
14
14
34
34
17
Responses
46
46
14
14
34
34
17
Answers
Answered by
GPT-4o mini
To find the length of one of the sides of rhombus QRST, we can use the property that the diagonals of a rhombus bisect each other at right angles.
Given that:
- \( QS = 30 \)
- \( RT = 16 \)
Since the diagonals bisect each other, we can find the lengths of segments \( QU \) and \( RU \):
\[
QU = \frac{QS}{2} = \frac{30}{2} = 15
\]
\[
RU = \frac{RT}{2} = \frac{16}{2} = 8
\]
Now, we can use the Pythagorean theorem to find the length of one side of the rhombus (let's call it \( s \)).
In triangle \( QUR \):
\[
s^2 = QU^2 + RU^2
\]
Substituting the values:
\[
s^2 = 15^2 + 8^2
\]
\[
s^2 = 225 + 64
\]
\[
s^2 = 289
\]
\[
s = \sqrt{289} = 17
\]
Thus, the length of one of the sides of the rhombus is \( \boxed{17} \).
Given that:
- \( QS = 30 \)
- \( RT = 16 \)
Since the diagonals bisect each other, we can find the lengths of segments \( QU \) and \( RU \):
\[
QU = \frac{QS}{2} = \frac{30}{2} = 15
\]
\[
RU = \frac{RT}{2} = \frac{16}{2} = 8
\]
Now, we can use the Pythagorean theorem to find the length of one side of the rhombus (let's call it \( s \)).
In triangle \( QUR \):
\[
s^2 = QU^2 + RU^2
\]
Substituting the values:
\[
s^2 = 15^2 + 8^2
\]
\[
s^2 = 225 + 64
\]
\[
s^2 = 289
\]
\[
s = \sqrt{289} = 17
\]
Thus, the length of one of the sides of the rhombus is \( \boxed{17} \).
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