What should be the value of b in x^2+bx-55=0 so that its solutions are -11 and 5

A. -16
B. 6
C. -6
D. 16

1 answer

To find the value of \( b \) in the equation \( x^2 + bx - 55 = 0 \) such that its solutions are \( -11 \) and \( 5 \), we can use Vieta's formulas.

According to Vieta's formulas:

  1. The sum of the roots (solutions) is equal to \( -b \).
  2. The product of the roots is equal to the constant term.

Given the roots \( -11 \) and \( 5 \):

  1. Sum of the roots: \[ -11 + 5 = -6 \]

    Therefore, we know: \[ -b = -6 \implies b = 6 \]

  2. Product of the roots: \[ (-11) \times 5 = -55 \]

    This confirms the constant term is correct since \( -55 \) matches the equation \( x^2 + bx - 55 = 0 \).

Thus, the correct value of \( b \) is \( 6 \).

The answer is \( \boxed{6} \).