Asked by skyler cooley
which of the following correctly identifies the quadratic function that is related to the square root function k (x) = 5 sq rt x ?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the quadratic function related to the square root function \( k(x) = 5 \sqrt{x} \), we start by expressing \( k(x) \) in terms of \( y \):
\[
y = 5 \sqrt{x}
\]
To convert this square root function into a quadratic function, we can square both sides of the equation to eliminate the square root:
\[
y^2 = (5 \sqrt{x})^2
\]
This simplifies to:
\[
y^2 = 25x
\]
Now, we can rewrite this equation in the standard form of a quadratic function:
\[
x = \frac{1}{25}y^2
\]
This shows that the quadratic function related to the square root function \( k(x) = 5 \sqrt{x} \) is:
\[
x = \frac{1}{25}y^2
\]
Alternatively, you can express it in terms of \( y \) as a function of \( x \) (if that was your intent), resulting in:
\[
y^2 = 25x
\]
For clarity, either of these forms can be viewed as a relationship involving a quadratic function derived from the given square root function.
\[
y = 5 \sqrt{x}
\]
To convert this square root function into a quadratic function, we can square both sides of the equation to eliminate the square root:
\[
y^2 = (5 \sqrt{x})^2
\]
This simplifies to:
\[
y^2 = 25x
\]
Now, we can rewrite this equation in the standard form of a quadratic function:
\[
x = \frac{1}{25}y^2
\]
This shows that the quadratic function related to the square root function \( k(x) = 5 \sqrt{x} \) is:
\[
x = \frac{1}{25}y^2
\]
Alternatively, you can express it in terms of \( y \) as a function of \( x \) (if that was your intent), resulting in:
\[
y^2 = 25x
\]
For clarity, either of these forms can be viewed as a relationship involving a quadratic function derived from the given square root function.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.