Asked by Khin
Identify the spectator ion(s) in the following reaction:
Cu(OH)2(s) + 2H+(aq) + 2Cl–(aq) Cu2+(aq) + 2Cl–(aq) + 2H2O(l)
a. Cu2+ and Cl-
b. H+ and Cl–
c. Cu(OH)2
d. Cl–
e. Cu2+
Cu(OH)2(s) + 2H+(aq) + 2Cl–(aq) Cu2+(aq) + 2Cl–(aq) + 2H2O(l)
a. Cu2+ and Cl-
b. H+ and Cl–
c. Cu(OH)2
d. Cl–
e. Cu2+
Answers
Answered by
DrBob222
With no arrow it is difficult to know which are the reactants and which are the products. To answer your question:
1. Write the arrow where it belongs and do that EVERY time you write an equation. You CAN'T omit the arrow and know what you're doing.
2. Identify the ions on each side of the arrow that are common. Those are the spectator ions.
1. Write the arrow where it belongs and do that EVERY time you write an equation. You CAN'T omit the arrow and know what you're doing.
2. Identify the ions on each side of the arrow that are common. Those are the spectator ions.
Answered by
constantine
Cu(OH)2
Answered by
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