Question

Multiply the polynomials $(3x-1)(2x+4)$ (2 points)
$\vert x^{2}+\vert \quad x+$

Answer 1

To multiply the polynomials \((3x - 1)(2x + 4)\), we can use the distributive property (also known as the FOIL method for binomials).

Let's multiply each term in the first polynomial by each term in the second polynomial:

\[
(3x - 1)(2x + 4)
\]

1. **First:** Multiply the first terms:
\[
3x \cdot 2x = 6x^2
\]

2. **Outer:** Multiply the outer terms:
\[
3x \cdot 4 = 12x
\]

3. **Inner:** Multiply the inner terms:
\[
-1 \cdot 2x = -2x
\]

4. **Last:** Multiply the last terms:
\[
-1 \cdot 4 = -4
\]

Now we combine all these results:
\[
6x^2 + 12x - 2x - 4
\]

Combine like terms:
\[
6x^2 + (12x - 2x) - 4 = 6x^2 + 10x - 4
\]

Thus, the product of the polynomials \((3x - 1)(2x + 4)\) is:

\[
\boxed{6x^2 + 10x - 4}
\]