Ask a New Question
Menu

Multiply the polynomials $(3x-1)(2x+4)$ (2 points)

$\vert x^{2}+\vert \quad x+$

1 answer

To multiply the polynomials \((3x - 1)(2x + 4)\), we can use the distributive property (also known as the FOIL method for binomials).

Let's multiply each term in the first polynomial by each term in the second polynomial:

\[ (3x - 1)(2x + 4) \]

  1. First: Multiply the first terms: \[ 3x \cdot 2x = 6x^2 \]

  2. Outer: Multiply the outer terms: \[ 3x \cdot 4 = 12x \]

  3. Inner: Multiply the inner terms: \[ -1 \cdot 2x = -2x \]

  4. Last: Multiply the last terms: \[ -1 \cdot 4 = -4 \]

Now we combine all these results: \[ 6x^2 + 12x - 2x - 4 \]

Combine like terms: \[ 6x^2 + (12x - 2x) - 4 = 6x^2 + 10x - 4 \]

Thus, the product of the polynomials \((3x - 1)(2x + 4)\) is:

\[ \boxed{6x^2 + 10x - 4} \]