Question

Simplify the expression:

(6q + 1)(3) =

Answer 1

Simplify the expression:

2(2 + m) =

Answer 2

Simplify the expression:

(1 + x)(5) =

Answer 3

Simplify the expression:

2(3 + 6k)

Answer 4

Simplify the expression:

–3(5 − 4c)

Answer 5

Simplify the expression:

5(–2 − 7d)

Answer 6

To simplify the expression \((6q + 1)(3)\), you can distribute the \(3\) across the terms inside the parentheses:

\[
(6q + 1)(3) = 6q \cdot 3 + 1 \cdot 3
\]

Calculating each term, you get:

\[
6q \cdot 3 = 18q
\]
\[
1 \cdot 3 = 3
\]

Now, combine these results:

\[
18q + 3
\]

So, the simplified expression is:

\[
\boxed{18q + 3}
\]

Answer 7

To simplify the expression \(2(2 + m)\), you can distribute the \(2\) across the terms inside the parentheses:

\[
2(2 + m) = 2 \cdot 2 + 2 \cdot m
\]

Calculating each term:

\[
2 \cdot 2 = 4
\]
\[
2 \cdot m = 2m
\]

Now, combine these results:

\[
4 + 2m
\]

So, the simplified expression is:

\[
\boxed{4 + 2m}
\]

Answer 8

To simplify the expression \((1 + x)(5)\), you distribute the \(5\) across the terms inside the parentheses:

\[
(1 + x)(5) = 1 \cdot 5 + x \cdot 5
\]

Calculating each term, you get:

\[
1 \cdot 5 = 5
\]
\[
x \cdot 5 = 5x
\]

Now, combine these results:

\[
5 + 5x
\]

So, the simplified expression is:

\[
\boxed{5 + 5x}
\]

Answer 9

To simplify the expression \(2(3 + 6k)\), you distribute the \(2\) across the terms inside the parentheses:

\[
2(3 + 6k) = 2 \cdot 3 + 2 \cdot 6k
\]

Calculating each term gives:

\[
2 \cdot 3 = 6
\]
\[
2 \cdot 6k = 12k
\]

Now, combine these results:

\[
6 + 12k
\]

So, the simplified expression is:

\[
\boxed{6 + 12k}
\]

Answer 10

To simplify the expression \(-3(5 - 4c)\), you distribute the \(-3\) across the terms inside the parentheses:

\[
-3(5 - 4c) = -3 \cdot 5 + (-3) \cdot (-4c)
\]

Calculating each term gives:

\[
-3 \cdot 5 = -15
\]
\[
-3 \cdot (-4c) = 12c
\]

Now, combine these results:

\[
-15 + 12c
\]

So, the simplified expression is:

\[
\boxed{-15 + 12c}
\]

Answer 11

To simplify the expression \(5(-2 - 7d)\), you will distribute the \(5\) across the terms inside the parentheses:

\[
5(-2 - 7d) = 5 \cdot (-2) + 5 \cdot (-7d)
\]

Calculating each term gives:

\[
5 \cdot (-2) = -10
\]
\[
5 \cdot (-7d) = -35d
\]

Now, combine these results:

\[
-10 - 35d
\]

So, the simplified expression is:

\[
\boxed{-10 - 35d}
\]