Question

Find the sum of the partial products for 45×21
.

(1 point)
Responses

400+100+40+1=541
400 + 100 + 40 + 1 = 541

400+100+50+5=555
400 + 100 + 50 + 5 = 555

800+100+50+5=955
800 + 100 + 50 + 5 = 955

800+100+40+5=945

Answer 1

To calculate the sum of the partial products for \( 45 \times 21 \), we can break it down as follows:

1. Break down the numbers:
- \( 45 = 40 + 5 \)
- \( 21 = 20 + 1 \)

2. Write out the partial products:
- \( 40 \times 20 = 800 \)
- \( 40 \times 1 = 40 \)
- \( 5 \times 20 = 100 \)
- \( 5 \times 1 = 5 \)

3. Now, sum the partial products:
- \( 800 + 40 + 100 + 5 = 945 \)

Thus, the correct response is:
**800 + 100 + 40 + 5 = 945.**