Question

Rosa pays a monthly membership fee at a gym. She also pays $5 for each cycling class she takes. In May, she took 4 cycling classes and her total cost for the month was $55. In June, Rosa’s total cost was equal to twice the membership fee. How many cycling classes did Rosa take in June?
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1 point
5
6
7
8

Answer 1

Let \( m \) be the monthly membership fee.

In May, Rosa took 4 cycling classes, so her total cost can be expressed as:

\[
\text{Total Cost} = m + 5 \times 4
\]

This simplifies to:

\[
\text{Total Cost} = m + 20
\]

We know from the problem that this total cost was $55, so we can set up the equation:

\[
m + 20 = 55
\]

Solving for \( m \):

\[
m = 55 - 20 = 35
\]

So the monthly membership fee is \( m = 35 \).

In June, her total cost was equal to twice the membership fee:

\[
\text{Total Cost in June} = 2m = 2 \times 35 = 70
\]

Let \( c \) represent the number of cycling classes Rosa took in June. Therefore, her cost in June can be expressed as:

\[
70 = m + 5c
\]

Substituting \( m = 35 \):

\[
70 = 35 + 5c
\]

To find \( c \), we rearrange the equation:

\[
70 - 35 = 5c
\]
\[
35 = 5c
\]
\[
c = \frac{35}{5} = 7
\]

So, Rosa took **7 cycling classes** in June.

The answer is **7**.