To solve for the two numbers, we can use the system of equations given:
- \( x + y = 34 \) (Equation 1)
- \( x - y = 12 \) (Equation 2)
We can solve this system by using the elimination or substitution method. Here, we will use the elimination method.
Start by adding Equation 1 and Equation 2:
\[ (x + y) + (x - y) = 34 + 12 \]
This simplifies to:
\[ 2x = 46 \]
Now, divide both sides by 2:
\[ x = 23 \]
Now that we have \( x \), substitute \( x = 23 \) back into Equation 1 to find \( y \):
\[ 23 + y = 34 \]
Subtract 23 from both sides:
\[ y = 34 - 23 = 11 \]
Thus, the two numbers are \( x = 23 \) and \( y = 11 \).
So the answer is 23 and 11.