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Jen,amy,linda,max and jenny are compteting to fill two remaining spots on the chess team. How mant different combinations are possible for filling the two spots?

120,60,20,or 10
15 years ago

Answers

PsyDAG
Let s = spots and n = number of students

n! = "n factorial" = product of all numbers n or less

P = n!/s!(n-s)! = 5!/2!(5-2)!

5! = 5 * 4 * 3 * 2 *1 = 120
2! = 2 * 1 = 2
(5-2)! = 3! = 3 * 2 * 1 = 6

P = 120/12 = 10
15 years ago

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