Asked by Joe

Jen,amy,linda,max and jenny are compteting to fill two remaining spots on the chess team. How mant different combinations are possible for filling the two spots?

120,60,20,or 10

Answers

Answered by PsyDAG
Let s = spots and n = number of students

n! = "n factorial" = product of all numbers n or less

P = n!/s!(n-s)! = 5!/2!(5-2)!

5! = 5 * 4 * 3 * 2 *1 = 120
2! = 2 * 1 = 2
(5-2)! = 3! = 3 * 2 * 1 = 6

P = 120/12 = 10
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