Question

Use the Distributive Property to rewrite the expression $(3x-5)(2x+2)$
(1 point)
$6x^{2}-3x-10$
$6x^{2}-4x-10$
$x^{2}-3x-10$
$5x^{2}-2x-3$

Answer 1

To rewrite the expression \((3x-5)(2x+2)\) using the Distributive Property, we will distribute each term in the first parenthesis by each term in the second parenthesis.

1. Distribute \(3x\):
\[
3x \cdot 2x = 6x^2
\]
\[
3x \cdot 2 = 6x
\]

2. Distribute \(-5\):
\[
-5 \cdot 2x = -10x
\]
\[
-5 \cdot 2 = -10
\]

Now, combine all these results:
\[
6x^2 + 6x - 10x - 10
\]

Now combine the \(x\) terms:
\[
6x^2 + (6x - 10x) - 10 = 6x^2 - 4x - 10
\]

Thus, the expression \((3x-5)(2x+2)\) rewritten using the Distributive Property is:
\[
\boxed{6x^2 - 4x - 10}
\]