Question
question.
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A measuring cylinder contains 50 cm ^3 of water. A stone has a mass of 1.75 g the stone is lowered into the cylinder rises to 52.5 cm^3 calculate the density of the stone.
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A measuring cylinder contains 50 cm ^3 of water. A stone has a mass of 1.75 g the stone is lowered into the cylinder rises to 52.5 cm^3 calculate the density of the stone.
Answers
GPT-4o mini
To find the density of the stone, we can use the formula for density:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
1. **Mass of the stone (m)**: 1.75 g
2. **Volume of the stone (V)**:
- Initial volume of water = 50 cm³
- Final volume of water after placing the stone = 52.5 cm³
- Volume of the stone = Final volume - Initial volume = \(52.5 \, \text{cm}^3 - 50 \, \text{cm}^3 = 2.5 \, \text{cm}^3\)
3. **Calculate the density**:
\[
\text{Density} = \frac{1.75 \, \text{g}}{2.5 \, \text{cm}^3} = 0.7 \, \text{g/cm}^3
\]
Therefore, the density of the stone is **0.7 g/cm³**.
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
1. **Mass of the stone (m)**: 1.75 g
2. **Volume of the stone (V)**:
- Initial volume of water = 50 cm³
- Final volume of water after placing the stone = 52.5 cm³
- Volume of the stone = Final volume - Initial volume = \(52.5 \, \text{cm}^3 - 50 \, \text{cm}^3 = 2.5 \, \text{cm}^3\)
3. **Calculate the density**:
\[
\text{Density} = \frac{1.75 \, \text{g}}{2.5 \, \text{cm}^3} = 0.7 \, \text{g/cm}^3
\]
Therefore, the density of the stone is **0.7 g/cm³**.