Solve the following system of equations using the elimination method.

0.1x+0.3y=0.9
, 0.1x−0.3y=0.2


(1 point)
Responses

(112,76)
left parenthesis Start Fraction 11 over 2 End Fraction comma Start Fraction 7 over 6 End Fraction right parenthesis

(112,−76)
left parenthesis Start Fraction 11 over 2 End Fraction comma negative Start Fraction 7 over 6 End Fraction right parenthesis

(−76,112)
left parenthesis negative Start Fraction 7 over 6 End Fraction comma Start Fraction 11 over 2 End Fraction right parenthesis

There is no solution

1 answer

To solve the given system of equations using the elimination method, we start with the following equations:

  1. \( 0.1x + 0.3y = 0.9 \) (Equation 1)
  2. \( 0.1x - 0.3y = 0.2 \) (Equation 2)

To eliminate \( y \), we can add the two equations together:

\[ (0.1x + 0.3y) + (0.1x - 0.3y) = 0.9 + 0.2 \]

This simplifies to:

\[ 0.2x = 1.1 \]

Next, we solve for \( x \):

\[ x = \frac{1.1}{0.2} = 5.5 \]

Now, substituting \( x = 5.5 \) back into one of the original equations to solve for \( y \). We can use Equation 1:

\[ 0.1(5.5) + 0.3y = 0.9 \]

Calculate \( 0.1(5.5) \):

\[ 0.55 + 0.3y = 0.9 \]

Subtract \( 0.55 \) from both sides:

\[ 0.3y = 0.9 - 0.55 \] \[ 0.3y = 0.35 \]

Now, solve for \( y \):

\[ y = \frac{0.35}{0.3} = \frac{35}{30} = \frac{7}{6} \]

Thus, the solution to the system of equations is:

\[ (x, y) = \left(5.5, \frac{7}{6}\right) = \left(\frac{11}{2}, \frac{7}{6}\right) \]

Considering the response options, the correct one matches:

\[ \left( \frac{11}{2}, \frac{7}{6} \right) \]