To determine which object would reach 100 feet in the least amount of time, we need to analyze the slopes (rates of distance per time) of the lines A, B, and C:
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Line A: It passes through the points (0, 0) and (3, 6). The slope is calculated as follows: \[ \text{slope}_A = \frac{6 - 0}{3 - 0} = \frac{6}{3} = 2 \text{ feet/second} \]
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Line B: It passes through the points (0, 0) and (6, 6): \[ \text{slope}_B = \frac{6 - 0}{6 - 0} = \frac{6}{6} = 1 \text{ foot/second} \]
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Line C: It passes through the points (0, 0) and (6, 3): \[ \text{slope}_C = \frac{3 - 0}{6 - 0} = \frac{3}{6} = 0.5 \text{ feet/second} \]
Now, we can calculate the time it takes for each object to reach 100 feet using the formula: \[ \text{time} = \frac{\text{distance}}{\text{rate}} \]
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For Object A: \[ \text{time}_A = \frac{100}{2} = 50 \text{ seconds} \]
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For Object B: \[ \text{time}_B = \frac{100}{1} = 100 \text{ seconds} \]
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For Object C: \[ \text{time}_C = \frac{100}{0.5} = 200 \text{ seconds} \]
Based on these calculations, Object A would reach 100 feet in the least amount of time, which is 50 seconds.
Therefore, the answer is:
object A