To determine the number of real solutions for the equation \(-6x^2 - 108 = 0\), we first rearrange it in the standard quadratic form \(ax^2 + bx + c = 0\).
The equation can be rewritten as: \[ -6x^2 = 108 \implies 6x^2 = -108 \] However, reversing the sign gives: \[ 6x^2 + 108 = 0 \]
Identifying coefficients:
- \(a = 6\)
- \(b = 0\)
- \(c = 108\)
The discriminant \(D\) is given by the formula: \[ D = b^2 - 4ac \]
Now, substituting in the values we have: \[ D = 0^2 - 4(6)(108) = 0 - 2592 = -2592 \]
Since the discriminant \(D\) is negative, we conclude that there are no real solutions for the equation.
Therefore, the correct statement is: There will be no real solutions since the discriminant is negative.