To find the width of the park, we can divide the area of the park by its length.
The area \( A \) of the park is given as:
\[ A = 1.36 \times 10^8 \times f \times t^2 \]
The length \( L \) of the park is given as:
\[ L = 1.6 \times 10^4 \text{ ft} \]
We can use the formula for the area of a rectangle, which is:
\[ A = L \times W \]
where \( W \) is the width. Rearranging this gives:
\[ W = \frac{A}{L} \]
Substituting the values for \( A \) and \( L \):
\[ W = \frac{1.36 \times 10^8 \times f \times t^2}{1.6 \times 10^4} \]
Now, we need to perform the division:
- Divide the coefficients: \( \frac{1.36}{1.6} = 0.85 \).
- Use the properties of exponents to simplify \( \frac{10^8}{10^4} = 10^{8-4} = 10^4 \).
Putting it all together, we get:
\[ W = 0.85 \times 10^4 \times f \times t^2 \]
This can also be expressed in scientific notation:
\[ W = 8.5 \times 10^3 \times f \times t^2 \]
Therefore, the width of the park is:
\[ W = 8.5 \times 10^3 \times f \times t^2 \text{ ft} \]