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Neil has a bucket of beads. He uses him to make eight identical necklaces, and then buys 25 beads at the store. He ends up with...
Niel has a bucket of beads. He uses them to make 8 identical necklaces and then buys 25 beads at the store. He ends up with a total of 500 beads. How many did he start with? Identify the operations needed to solve this problem using the equation b/8 + 25 = 500
.(1 point)
Responses
subtraction and division
subtraction and division
addition and division
addition and division
addition and multiplication
addition and multiplication
subtraction and multiplication
.(1 point)
Responses
subtraction and division
subtraction and division
addition and division
addition and division
addition and multiplication
addition and multiplication
subtraction and multiplication
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the problem using the equation \( \frac{b}{8} + 25 = 500 \), we can analyze the operations involved:
1. **Subtraction**: The first step is to isolate the term involving \( b \) on one side of the equation. This can be achieved by subtracting 25 from both sides:
\[
\frac{b}{8} + 25 - 25 = 500 - 25 \Rightarrow \frac{b}{8} = 475
\]
2. **Multiplication**: Next, to solve for \( b \), we need to eliminate the fraction by multiplying both sides by 8:
\[
8 \cdot \frac{b}{8} = 475 \cdot 8 \Rightarrow b = 3800
\]
Given this analysis, the operations needed are **subtraction and multiplication**.
Therefore, the correct response is:
**subtraction and multiplication**
1. **Subtraction**: The first step is to isolate the term involving \( b \) on one side of the equation. This can be achieved by subtracting 25 from both sides:
\[
\frac{b}{8} + 25 - 25 = 500 - 25 \Rightarrow \frac{b}{8} = 475
\]
2. **Multiplication**: Next, to solve for \( b \), we need to eliminate the fraction by multiplying both sides by 8:
\[
8 \cdot \frac{b}{8} = 475 \cdot 8 \Rightarrow b = 3800
\]
Given this analysis, the operations needed are **subtraction and multiplication**.
Therefore, the correct response is:
**subtraction and multiplication**
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