I'm sorry, but I cannot access specific external articles, including "Planet" by William A. Gutsch Jr. However, I can provide general information about the average distances of the planets from the Sun, represented in scientific notation, and help you with the calculations.
Here is a list of the average distances of the planets from the Sun in astronomical units (AU), where 1 AU is approximately \(1.496 \times 10^{11}\) meters. The distances of the planets in AU are approximately:
- Mercury: \(0.39 , \text{AU} = 3.9 \times 10^{10} , \text{m}\)
- Venus: \(0.72 , \text{AU} = 7.2 \times 10^{10} , \text{m}\)
- Earth: \(1.00 , \text{AU} = 1.0 \times 10^{11} , \text{m}\)
- Mars: \(1.52 , \text{AU} = 1.52 \times 10^{11} , \text{m}\)
- Jupiter: \(5.20 , \text{AU} = 5.2 \times 10^{11} , \text{m}\)
- Saturn: \(9.58 , \text{AU} = 9.58 \times 10^{11} , \text{m}\)
- Uranus: \(19.22 , \text{AU} = 1.922 \times 10^{12} , \text{m}\)
- Neptune: \(30.05 , \text{AU} = 3.005 \times 10^{12} , \text{m}\)
a. List of Distances from Each Planet to the Sun (in Scientific Notation):
- Mercury: \(3.9 \times 10^{10} , \text{m}\)
- Venus: \(7.2 \times 10^{10} , \text{m}\)
- Earth: \(1.0 \times 10^{11} , \text{m}\)
- Mars: \(1.52 \times 10^{11} , \text{m}\)
- Jupiter: \(5.2 \times 10^{11} , \text{m}\)
- Saturn: \(9.58 \times 10^{11} , \text{m}\)
- Uranus: \(1.922 \times 10^{12} , \text{m}\)
- Neptune: \(3.005 \times 10^{12} , \text{m}\)
b. Addition of Two Distances
Let’s add the distances of Earth and Mars.
\[ 1.0 \times 10^{11} + 1.52 \times 10^{11} = (1.0 + 1.52) \times 10^{11} = 2.52 \times 10^{11} , \text{m} \]
c. Subtraction of Two Distances
Let’s subtract the distance of Venus from the distance of Saturn.
\[ 9.58 \times 10^{11} - 7.2 \times 10^{10} = 9.58 \times 10^{11} - 0.72 \times 10^{11} = (9.58 - 0.72) \times 10^{11} = 8.86 \times 10^{11} , \text{m} \]
d. Multiplication of Two Distances
Let’s multiply the distances of Mercury and Venus.
\[ (3.9 \times 10^{10})(7.2 \times 10^{10}) = (3.9 \times 7.2) \times 10^{20} = 28.08 \times 10^{20} = 2.808 \times 10^{21} , \text{m}^2 \]
e. Division of Two Distances
Let’s divide the distance of Neptune by the distance of Jupiter.
\[ \frac{3.005 \times 10^{12}}{5.2 \times 10^{11}} = \frac{3.005}{5.2} \times 10^{12-11} = 0.577 \times 10^{1} = 5.77 , \text{AU} \]
These calculations illustrate how to manipulate scientific notation for the distances of planets from the Sun. If you need further details, feel free to ask!