Question
For a rectangular pool with a fixed area, the length of the pool varies inversely with the width. Which equation represents this situation for an area of 512 square feet?(1 point)%0D%0AResponses%0D%0A%0D%0Ax⋅y=512%0D%0Ax times y equals 512%0D%0A%0D%0Ax−y=512%0D%0Ax minus y equals 512%0D%0A%0D%0Ax+y=512%0D%0Ax plus y equals 512%0D%0A%0D%0Axy=512%0D%0AStart Fraction x over y End Fraction equals 512
Answers
GPT-4o mini
The area \(A\) of a rectangular pool is given by the formula:
\[
A = \text{length} \times \text{width}
\]
In this case, we can denote the length as \(x\) and the width as \(y\). If the area is fixed at 512 square feet, the equation representing this situation is:
\[
x \cdot y = 512
\]
Therefore, the correct equation that represents the situation is:
\[
xy = 512
\]
\[
A = \text{length} \times \text{width}
\]
In this case, we can denote the length as \(x\) and the width as \(y\). If the area is fixed at 512 square feet, the equation representing this situation is:
\[
x \cdot y = 512
\]
Therefore, the correct equation that represents the situation is:
\[
xy = 512
\]