To interpret the range of the quadratic equation \( y = -\frac{1}{42}(x - 50)^2 + 60 \) in the context of a baseball game, we will analyze the features of the parabola.
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Understanding the Equation: The equation is in vertex form \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola. Here, \( a = -\frac{1}{42} \), which means the parabola opens downward, indicating that the ball reaches a maximum height.
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Finding the Vertex: The vertex of the parabola is at \((50, 60)\). This tells us that the maximum height the ball reaches is \( y = 60 \) feet when it is at a horizontal distance \( x = 50 \) feet from home plate.
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Identifying the Range: The equation also expresses a range of heights. Given that the parabola opens downward and has a maximum height of \( 60 \) at \( x = 50 \), the ball will fall back down to the ground as it travels further right (increasing \( x \)). The height \( y \) can reach as low as \( 0 \) feet, which is when the ball lands on the ground.
Therefore, the range \( 0 \leq y \leq 60 \) means that:
- 0 ≤ y: The height of the ball is never below 0 feet; it cannot travel underground (the ball cannot go lower than the ground level).
- y ≤ 60: The maximum height of the ball is 60 feet, the point at which it reaches its apex before descending.
Conclusion: In the context of this baseball game, the range of \( 0 \leq y \leq 60 \) indicates that the ball, once hit, will soar up to a maximum height of 60 feet above the ground before landing on the field at some point where its height reaches 0 feet again.