Asked by adrian
show that 3/2 and 1/3 are roots of the quadratic function y=6x2(squared)- 7x -3
Answers
Answered by
drwls
6x^2 -7x -3 = 0 can be factored to the form
(3x+1)(2x-3) = 0
If either factor is zero, you have a solution
The roots are actually -1/3 and +3/2. You left out a minus sign
(3x+1)(2x-3) = 0
If either factor is zero, you have a solution
The roots are actually -1/3 and +3/2. You left out a minus sign
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