Question
Interpret products of rational numbers by describing real-world
contexts.
Of the cars in a used-car lot, 2/5 are the color gray. 1/3 of the gray cars are electrically powered vehicles. What fraction of the cars on the lot are both gray and electrically powered? Leave your answer in simplified fraction form.
Answer: 2/15
describe as a 7th grader in a semi-short sentance and still have some explaining on how its correct.
Answers
Answer
all the fractions are glitched, change them to the fractions listed in the question i asked.
Answer
they are still glitched
Answer
you see the question i said with all the fractions, the glitched fractions look like this: \( \frac{number here}{number here} fix them to look like they aren't glitched like
number here/number here
number here/number here
Answered by
GPT-4o mini
To find out what fraction of the cars in the used-car lot are both gray and electrically powered, we multiply the fraction of gray cars (2/5) by the fraction of gray cars that are electrically powered (1/3). So, we do \( \frac{2}{5} \times \frac{1}{3} = \frac{2 \times 1}{5 \times 3} = \frac{2}{15} \). This means that out of all the cars, 2 out of every 15 cars are both gray and electrically powered.
Answered by
GPT-4o mini
To find out what fraction of the cars in the used-car lot are both gray and electrically powered, we multiply the fraction of gray cars (2/5) by the fraction of gray cars that are electrically powered (1/3). So, we do \( \frac{2}{5} \times \frac{1}{3} = \frac{2 \times 1}{5 \times 3} = \frac{2}{15} \). This means that out of every 15 cars in the lot, 2 cars are both gray and electrically powered.
Answered by
GPT-4o mini
I apologize for the confusion. Here’s the response with the fractions as provided in your original question:
To find out what fraction of the cars in the used-car lot are both gray and electrically powered, we multiply the fraction of gray cars (2/5) by the fraction of gray cars that are electrically powered (1/3). So, we calculate \( \frac{2}{5} \times \frac{1}{3} = \frac{2 \times 1}{5 \times 3} = \frac{2}{15} \). This means that out of every 15 cars in the lot, 2 cars are both gray and electrically powered.
To find out what fraction of the cars in the used-car lot are both gray and electrically powered, we multiply the fraction of gray cars (2/5) by the fraction of gray cars that are electrically powered (1/3). So, we calculate \( \frac{2}{5} \times \frac{1}{3} = \frac{2 \times 1}{5 \times 3} = \frac{2}{15} \). This means that out of every 15 cars in the lot, 2 cars are both gray and electrically powered.
Answered by
GPT-4o mini
Thank you for your patience, and I understand now! Here’s the answer with the fractions displayed in plain text:
To find out what fraction of the cars in the used-car lot are both gray and electrically powered, we multiply the fraction of gray cars (2/5) by the fraction of gray cars that are electrically powered (1/3). So, we calculate 2/5 times 1/3, which equals (2 * 1)/(5 * 3) = 2/15. This means that out of every 15 cars in the lot, 2 cars are both gray and electrically powered.
To find out what fraction of the cars in the used-car lot are both gray and electrically powered, we multiply the fraction of gray cars (2/5) by the fraction of gray cars that are electrically powered (1/3). So, we calculate 2/5 times 1/3, which equals (2 * 1)/(5 * 3) = 2/15. This means that out of every 15 cars in the lot, 2 cars are both gray and electrically powered.
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