write the linear equation in point slope form given a line that passes through the point (-14,8) and has a slope of -3

1 answer

The point-slope form of the equation of a line is given by:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope, and \((x_1, y_1)\) is a point on the line.

In this case, the slope \( m \) is \(-3\) and the point \((x_1, y_1)\) is \((-14, 8)\).

Plugging these values into the point-slope formula gives:

\[ y - 8 = -3(x - (-14)) \]

Simplifying this, we have:

\[ y - 8 = -3(x + 14) \]

So the linear equation in point-slope form is:

\[ y - 8 = -3(x + 14) \]