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To multiply the binomial \((a - b)\) three times, we are calculating \((a - b)(a - b)(a - b)\) or \((a - b)^3\).
Using the binomial expansion formula for \((x - y)^3\):
\[
(x - y)^3 = x^3 - 3x^2y + 3xy^2 - y^3
\]
we can substitute \(x\) with \(a\) and \(y\) with \(b\):
\[
(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3
\]
Thus, the result when multiplying the three binomials \((a - b)(a - b)(a - b)\) is:
\[
a^3 - 3a^2b + 3ab^2 - b^3
\]
So, the correct answer from your provided options is:
**a³ - 3a²b + 3ab² - b³**