To determine the correct distance for Earth in the scale model, we can set up a proportion based on the distances mentioned.
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The distance of Mercury from the Sun in the model is 10 cm for 60,000,000 km:
- This gives us a scale factor of \( \frac{10 \text{ cm}}{60,000,000 \text{ km}} \).
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Now, we can find the distance for Earth, which is approximately 150,000,000 km:
- Let \( d \) be the distance from the dot for Earth, then: \[ \frac{10 \text{ cm}}{60,000,000 \text{ km}} = \frac{d}{150,000,000 \text{ km}} \]
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Cross-multiplying gives us: \[ 10 \text{ cm} \cdot 150,000,000 \text{ km} = d \cdot 60,000,000 \text{ km} \]
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Solving for \( d \): \[ d = \frac{10 \text{ cm} \cdot 150,000,000 \text{ km}}{60,000,000 \text{ km}} \]
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Simplifying this: \[ d = \frac{10 \cdot 150}{60} \text{ cm} \] \[ d = \frac{1500}{60} \text{ cm} \] \[ d = 25 \text{ cm} \]
Thus, the distance from the dot that Earth should be placed in the model is 25 cm.