find the absolute error in r=(420+/-5)+(100+/-3)

1 answer

To calculate the absolute error in \( r = (420 \pm 5) + (100 \pm 3) \), we first need to determine the absolute errors of the individual quantities and then combine them.

Given:

  • Quantity 1: \( 420 \pm 5 \)
  • Quantity 2: \( 100 \pm 3 \)

Step 1: Identify the absolute errors

  • Absolute error of Quantity 1: \( \Delta A = 5 \)
  • Absolute error of Quantity 2: \( \Delta B = 3 \)

Step 2: Combine the absolute errors

When adding two quantities, the absolute error of the sum is the sum of the absolute errors:

\[ \Delta r = \Delta A + \Delta B \]

\[ \Delta r = 5 + 3 = 8 \]

Step 3: Calculate the sum

Now, we can calculate the total value of \( r \):

\[ r = 420 + 100 = 520 \]

Final result

Thus, the result with its absolute error is:

\[ r = 520 \pm 8 \]

So, the absolute error in \( r \) is \( 8 \).