Asked by jose

what is the maximum number of grams of PH3 that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form PH3

Answers

Answered by Mohamed
Okay first lets figure out the equation
P+H2---->PH3
balance it now
we have: 2P + 3H2 --->2PH3
equation is now balanced.

let us now find the reactant in excess
2 moles of P= 3 moles of H2
2(31)g of P = 3(2)g of H2
6.2 g of P= x

x= 6.2x6/62= 0.6 g of H2

4 grams of H2 are reacting which proves that H2 is the reactant in excess since only 0.6 grams were needed.

So we use the limited reactant P to find out the mass of PH3 formed.
6.2 g of P = x
2(31)g of P= 2(31+3g) of PH3

68 g x 6.2g/62 g
= 6.8 g of PH3
I hope I am correct
Answered by DrBob222
The answer by mohamed is correct except your teacher may have instructed you to write P as P4. If so that will change the equation but it will not change the number of grams PH3 formed.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions