Question

((5v)/(v^3-5v^2+6v))-((4)/(v-2))-((3V)/(3-V))

Answer 1

First, factor out the v in the
(5v)/(v^3-5v^2+6v)) term.
That will leave you with
5/(v^2-5v+6) = 5/[(v-2)(v-3)]

Then use the method of partial fractions to rewrite that as
A/(v-2) + B/(v-3)

Determine the values of the constants A and B, and then combine with the last two terms, which have the same denominators.

If you are unfamiliar with the method of partial fractions, you may need to learn the method or review your text. It is easy to find tutorials online.