Which two equations form a system with no solutions (same slope but different y intercept)? **Hint: You must write # 4 - #6 in y = mx + b format first.

1. y=5x-4
2. y= -2x+3
3. y= 3x+1
4. 2y=6x+2
5. y-5x=2
6. y-4x+1=0

Option 1
Option 2
Option 3
Option 4
Option 5
Option 6

1 answer

To determine which two equations from the provided list form a system with no solutions, we need to convert any equations that are not already in slope-intercept form (y=mx+b) into that format.

Let’s convert equations #4, #5, and #6 into slope-intercept form:

  1. 2y=6x+2

    Divide everything by 2: y=3x+1

  2. y5x=2

    Rearranging to slope-intercept form: y=5x+2

  3. y4x+1=0

    Rearranging to get y by itself: y=4x1

Now we have the following equations in slope-intercept form:

  1. y=5x4
  2. y=2x+3
  3. y=3x+1
  4. y=3x+1
  5. y=5x+2
  6. y=4x1

Next, we need to identify pairs of equations that have the same slope (m) but different y-intercepts (b).

  1. Equation 1: Slope = 5, Intercept = -4
  2. Equation 2: Slope = -2, Intercept = 3
  3. Equation 3: Slope = 3, Intercept = 1
  4. Equation 4: (Identical to #3) Slope = 3, Intercept = 1
  5. Equation 5: Slope = 5, Intercept = 2
  6. Equation 6: Slope = 4, Intercept = -1

From the slopes:

  • Equations 1 and 5 both have a slope of 5 but different intercepts (-4 and 2).
  • Equations 3 and 4 are identical (same slope and intercept).
  • Equations 2 and 6 do not have the same slope as any other equation.

Thus, the pairs of equations with the same slope but different y-intercepts, leading to no solutions, are:

  • Equation 1 (y = 5x - 4) and Equation 5 (y = 5x + 2).

Therefore, the answer is: Option 1 and Option 5.