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The value of the equilibrium constant (Kp) as represented by the first chemical equation is 1.80 x 10-2 at 500 K. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer in scientific notation.
2NOCl(g) = 2NO(g)+Cl2(g)
2NO(g)+Cl2(g) = 2NOCl(g)
2NOCl(g) = 2NO(g)+Cl2(g)
2NO(g)+Cl2(g) = 2NOCl(g)
The answer is just the reciprocal of the first Kp. So in your calculator type in 1/1.80e-2 and that will be your answer for the Kp of the second equation at the same temperature.
The answer will be (in scientific notation): 5.56e1
The answer will be (in scientific notation): 5.56e1